ode internal name "second_order_series_method_regular_singular_point_repeated_root".
In this case the solution is
Where
\(r_{1},r_{2}\) are roots of the indicial equation. \(a_{0},b_{0}\) are set to \(1\) as arbitrary. The coefficients \(b_{n}\) are not found from the recurrence relation but found using using \(b_{n}=\frac {d}{dr}a_{n}\left ( r\right ) \) after finding \(a_{n}\) first, and the result evaluated at root \(r_{2}\). (notice that \(r=r_{1}=r_{2}\) in this case). Notice there is no \(C\) term in from of the \(\ln \) in this case as when root differ by an integer and the sum on \(b_{n}\) starts at \(1\) since \(b_{0}\) is always zero due to \(\frac {d}{dr}a_{0}\left ( r\right ) =0\) always as \(a_{0}=1\) by default.