[next] [prev] [prev-tail] [tail] [up]
Find \(x[n]\), give its DTFT \(X(\Omega )\)
Mathematica
Clear["Global`*"]; x[n_] := Sin[(Pi*n)/8]; X = FourierSequenceTransform[x[n], n, w, FourierParameters -> {1, 1}]; InverseFourierSequenceTransform[X, w, n]
Which gives
Sin[(Pi*n)/8]
[next] [prev] [prev-tail] [front] [up]