current database for the bridge, in the format of SDB SAP2000 1.5 version is SBD file
Results of each step are given in separate section. Each section has two parts, the first shows the results and the second describes the methods and analysis performed to obtain the results.
Joint | U1 | U2 | U3 | R1 | R2 | R3 |
ft | ft | ft | rad | rad | rad | |
S07L | 0.000179 | -0.003174 | 0.021538 | -0.000119 | 0.000098 | 4.253E-06 |
S15L | 0.000035 | -0.003104 | -0.032437 | -0.000216 | -0.001357 | 0.000029 |
Joint | U1 | U2 | U3 | R1 | R2 | R3 |
ft | ft | ft | rad | rad | rad | |
21 | 0.007568 | -0.002749 | -0.024066 | -0.000011 | 0.001533 | -0.000120 |
Problem description is
There are the steps performed
Figure 3.1 shows part of the joints coordinates table after completing the above steps.
SAP2000 v15.0.1 5/2/13 22:18:29 Table: Joint Coordinates Joint CoordSys CoordType XorR Y Z SpecialJt GlobalX GlobalY GlobalZ ft ft ft ft ft ft 1 GLOBAL Cartesian -4.1200 122.2500 74.0750 No -4.1200 122.2500 74.0750 2 GLOBAL Cartesian 4.1200 122.2500 74.0750 No 4.1200 122.2500 74.0750 3 GLOBAL Cartesian -7.9700 152.5000 58.2900 No -7.9700 152.5000 58.2900 4 GLOBAL Cartesian 7.9500 152.5000 58.2900 No 7.9500 152.5000 58.2900 5 GLOBAL Cartesian 0.0000 175.8000 36.1100 Yes 0.0000 175.8000 36.1100 6 GLOBAL Cartesian 0.0000 175.8000 53.3800 Yes 0.0000 175.8000 53.3800 7 GLOBAL Cartesian 6.0000 175.0000 53.3800 Yes 6.0000 175.0000 53.3800 8 GLOBAL Cartesian -6.0000 175.0000 53.3800 Yes -6.0000 175.0000 53.3800 9 GLOBAL Cartesian 3.5600 157.8000 54.5400 No 3.5600 157.8000 54.5400 10 GLOBAL Cartesian -3.5600 157.8000 54.5400 No -3.5600 157.8000 54.5400 11 GLOBAL Cartesian 0.0000 219.2000 50.7300 Yes 0.0000 219.2000 50.7300 12 GLOBAL Cartesian 0.0000 219.2000 39.3100 Yes 0.0000 219.2000 39.3100 13 GLOBAL Cartesian 0.0000 219.2000 32.7400 Yes 0.0000 219.2000 32.7400 14 GLOBAL Cartesian 12.0000 217.6000 50.7300 Yes 12.0000 217.6000 50.7300 15 GLOBAL Cartesian -12.0000 217.6000 39.3100 Yes -12.0000 217.6000 39.3100 16 GLOBAL Cartesian -7.0000 179.7600 36.7400 Yes -7.0000 179.7600 36.7400 17 GLOBAL Cartesian 0.0000 265.5700 29.8700 Yes 0.0000 265.5700 29.8700 18 GLOBAL Cartesian 0.0000 265.5700 42.5100 Yes 0.0000 265.5700 42.5100 19 GLOBAL Cartesian 0.0000 265.5700 44.8600 Yes 0.0000 265.5700 44.8600 20 GLOBAL Cartesian 0.0000 265.5700 47.0300 Yes 0.0000 265.5700 47.0300 21 GLOBAL Cartesian 18.0000 263.1700 47.0300 Yes 18.0000 263.1700 47.0300 22 GLOBAL Cartesian -18.0000 263.2000 42.5100 Yes -18.0000 263.2000 42.5100 23 GLOBAL Cartesian 0.0000 283.5700 44.8600 Yes 0.0000 283.5700 44.8600
Connected the joints added above to the bridge in order to establish the ramp. Figure 3.2 is screen shot showing the ramp connected to bridge. RBEAM elements are used.
10 kips downwards load at joint S15L was added. This was done by clicking on the joint and right clicking again. Using the pop up menu that appeared the value minus 10 was entered. Minus sign was used since load is downwards. The load pattern selected was S15L. Figure 3.3 shows the result.
Clicked on RUN ANALYSIS. In the set load case to run case S15L was the only one selected. All other load cases, including DEAD was not selected. This was done to obtain result due to vertical load only. Model was locked now. After run was completed, clicked on DISPLAY->SHOW TABLES->JOINT DISPACEMENTS and located nodes S15L and S07L to find the node displacements. Figure 3.4 shows the result of this step
SAP2000 v15.0.1 5/3/13 1:35:52 Table: Joint Displacements Joint OutputCase CaseType U1 U2 U3 R1 R2 R3 ft ft ft Radians Radians Radians S07L S15L LinStatic 0.000179 -0.003174 0.021538 -0.000119 0.000098 4.253E-06 S15L S15L LinStatic 0.000035 -0.003104 -0.032437 -0.000216 -0.001357 0.000029
10 kips downwards load at joint 21 was now added. This was done by clicking on the joint and right clicking aging. Using the pop-up menu that appeared the value minus 20 was entered. Minus sign was used since load is downwards. The load pattern selected was node20. Figure 3.5 shows this step.
Clicked on RUN ANALYSIS. In the setload case to run case node21 was the only one selected. All other load cases, including DEAD was not selected. This was done to obtain result due to vertical load only. Model was locked now. After run was completed, clicked on DISPLAY->SHOW TABLES->JOINT DISPACEMENTS and located nodes 21 to find the node displacements. Figure 3.6 shows the result.
SAP2000 v15.0.1 5/3/13 2:33:04 Table: Joint Displacements Joint OutputCase CaseType U1 U2 U3 R1 R2 R3 ft ft ft Radians Radians Radians 21 node21 LinStatic 0.007568 -0.002749 -0.024066 -0.000011 0.001533 -0.000120
The result is shown in table 3.2
Natural period \(T\) (sec) | Natural frequency \(f_n\) (hz) | critical damping ratio \(\zeta \) |
0.5 | 2.0 | 0.0014% |
This is the problem description
The above profile can be used as free the vibration profile. The method of logarithmic decrement was used to obtain the natural period and \(\zeta \) (damping critical coefficient). Figure 3.8 shows a closer zoom view of the above plot in order to estimate the period. It shows the natural period to be around 10 division.
The units used are sec*20, therefore natural period is \(T=\frac {10}{20}=0.5\) sec. Hence natural frequency is \(f=2\) hz.
To obtain the damping \(\zeta \), a number of methods can be used. The more accurate methods uses more peaks. Using \(N=35\) as number of peaks and using method of series expansion \(\zeta \) can be found. From the above plot the value of first peak is 55940 and value of peak number 35 was found to be 55770. Hence \begin {align*} \frac {y_0}{y_0+N} & = 1 + 2\pi N \zeta \\ \zeta & = \frac {1}{35(2\pi )} \frac {55940-55770}{55770}\\ & = 1.3861 \times 10^{-5}\\ & = 0.0014 \% \end {align*}
The following are the modal analysis results. Mode 3 has period 0.426531 seconds and natural frequency 2.3445 hz.
SAP2000 v15.0.1 5/3/13 3:29:56 Table: Modal Periods And Frequencies OutputCase StepType StepNum Period Frequency CircFreq Eigenvalue Sec Cyc/sec rad/sec rad2/sec2 Modal Mode 1.000000 0.486993 2.0534E+00 1.2902E+01 1.6646E+02 Modal Mode 2.000000 0.435780 2.2947E+00 1.4418E+01 2.0789E+02 Modal Mode 3.000000 0.426531 2.3445E+00 1.4731E+01 2.1700E+02 Modal Mode 4.000000 0.352227 2.8391E+00 1.7838E+01 3.1821E+02 Modal Mode 5.000000 0.321345 3.1119E+00 1.9553E+01 3.8231E+02 Modal Mode 6.000000 0.268232 3.7281E+00 2.3424E+01 5.4871E+02 Modal Mode 7.000000 0.258425 3.8696E+00 2.4313E+01 5.9114E+02 Modal Mode 8.000000 0.249385 4.0099E+00 2.5195E+01 6.3477E+02
In this description, reference is made to different view angles. Figure 3.48 shows the axis orientation used by SAP2000.
The maximum stress at the base of the column (label 11) in the ramp was also found for each mode. This was done using SAP2000 v15.1 which has this added feature. The following diagrams give stress S11 for each mode.
The nodes to find the displacements for are marked and given in figure ?? .
The result is shown below. The labels for local axes for joints are shown below, and are the same as the global axes. This is from SAP2000 help section
By default, the joint local 1-2-3 coordinate system is identical to the global X-Y-Z coordinate system
Therefore, U1 is in the X direction, and U2 in the Y direction, and U3 is the vertical displacement.
SAP2000 v15.0.1 5/4/13 1:02:04 Table: Joint Displacements Joint OutputCase StepType U1 U2 U3 R1 R2 R3 ft ft ft Radians Radians Radians 20 COMO Max 0.146711 0.019285 -0.000479 0.001667 0.015544 0.000542 20 COMO Min -0.141382 -0.017992 -0.000676 -0.001788 -0.013209 -0.000675 21 COMO Max 0.144476 0.034315 0.262294 0.002986 0.022603 0.001017 21 COMO Min -0.139764 -0.037636 -0.375865 0.000383 -0.015478 -0.001261 22 COMO Max 0.082805 0.009682 0.236030 0.003108 0.014103 -0.000012 22 COMO Min -0.083333 -0.005028 -0.305074 -0.000501 -0.018799 -0.000326 23 COMO Max 0.123308 0.015499 0.013802 0.001111 0.015690 0.000583 23 COMO Min -0.123593 -0.014890 -0.049072 -0.002825 -0.014603 -0.000494
Figure 3.19 shows screen shot of the deformed part of the ramp with the above joints marked on the diagram showing the relative displacement for better illustration.
The following text file contains the result for all nodes. step_4_beam_result.txt
In addition, below are plots of nodal displacements of node 20, on top of column labeled 11 on the ramp (this is the column being analyzed for stress). This plot shows that it took about 20 seconds for dynamic loading to settle down.
This means after 20 second of the marching band moving into the ramp, the ramp vibration reached steady state, therefore, the ramp is now vibrating at the same forcing frequency and transient response of the ramp has completed.
This is a plot the total axial load \(P\) on the column for the first 20 seconds.
This is movie of the first 20 seconds of the bridge vibration during marching band motion.
Node displacement for joint 20 under marching band (time history) is given below. The output is in this file node_20_final_displacement.txt
This is partial listing of the table from SAP2000.
SAP2000 v15.0.1 5/3/13 5:24:47 Table: Joint Displacements Joint OutputCase CaseType StepType StepNum U1 U2 U3 R1 R2 R3 ft ft ft Radians Radians Radians 20 MarchingBand LinModHist Time 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 20 MarchingBand LinModHist Time 0.021400 -3.745E-07 6.625E-08 2.712E-10 -7.568E-09 -3.795E-08 2.215E-09 20 MarchingBand LinModHist Time 0.042800 -2.849E-06 5.016E-07 2.063E-09 -5.715E-08 -2.887E-07 1.677E-08 20 MarchingBand LinModHist Time 0.064200 -8.717E-06 1.522E-06 6.310E-09 -1.726E-07 -8.828E-07 5.090E-08 20 MarchingBand LinModHist Time 0.085600 -0.000018 3.074E-06 1.289E-08 -3.463E-07 -1.804E-06 1.028E-07
Description of the problem is given below
The following are the steps performed
Load patterns are first defined. In SAP2000, a load case uses a load pattern. Hence a load pattern must first be be defined. Load pattern tells SAP where the loads are while a load cases tells SAP how to apply a specific load pattern, for example, either statically or dynamically and also tells SAP how to perform the analysis, for example, either using modal or direct integration.
Figure 3.24 shows the relation between load patterns and load cases as used in SAP2000.
The first load pattern is live load. This is the load of people on the bridge and is present all the time. The bridge is 10 ft wide, and the problem says to use 40 lb per square feet, or 400 lb per linear feet.
Selected DEFINE->LOAD PATTERNS and wrote LL in the Load Pattern Name window. selected LIVE as type, and set self weight multiplier to 0 then clicked Add New Load Pattern. Figure 3.25 shows this step.
Selected the floor of the bridge using SELECT->PROPERTIES->AREA SECTIONS->FLOOR. Added load LL using ASSIGN->AREA LOADS->UNIFORM(SHELL) and selected LL for load pattern. Used 0.04 for the load amount. This is 40 psf. (or 400 lb per linear ft, since the bridge is 10 ft wide). Figure 3.26 shows this step.
added 400 lb per linear ft also to on the ramp. SELECT->PROPERTIES->FRAME SECTIONS->RBEAM and as the ramp is selected clicked ASSIGN->FRAME LOAD->DISTRIBUTED LOAD and entered 400 (lb per linear ft). Load pattern LL was used. Figure 3.27 shows this step.
Added 10 kips per linear ft as distributed load on the first 4 RBEAMS on the right side of the ramp. Selected DYNALOAD as the load definition. Figure 3.28 shows this step.
Using the menu, selected DEFINE->FUNCTIONS->TIME HISTORY then selected From file and clicked on Add New Function... and gave it name and used the browser to locate the text file that contains the time history. The time history file was downloaded from the class web site.
Set VALUES AT EQUAL INTERVALS to 0.0214. Figure 3.29 shows this step.
Defined MODAL load case. Selected EIGN VECTOR and not RITZ Figure 3.30 shows this step.
Defined load case MarchingBand to use for time history loading to simulate the marching band on the ramp. Selected DYNALOAD as load pattern. Made sure to change the scale to 0.03. Figure 3.31 shows this step.
Defined a COMBINATION load case called COMO as shown in Figure 3.32
Modified mass and weight property of RBEAM by changing property modifier mass to 2.1762 and property modifier weight to 2.1748 as shown in Figure 3.33
PEAK DISPLACEMENT at end of cantilever beams extending from far north column are found. These are the sections called CANT3. The first beam is from node 20 to 21, the second beam from node 23 to 19, and the third beam from node 22 to 18.
Clicked on run and selected all cases to run. When run was completed, clicked on Display->Tables and clicked on Select load cases... and selected COMO. Then selected ANALYSIS RESULTS followed by Joint Output->Displacements->Table.
Searched the table of joint Displacements for the 3 beams given above.
In this step, peak stress calculations at the bottom of came column under the peak marching band are made. A Matlab script was written to do the computation based on result obtained from SAP tables.
Maximum tensile and compressive stress due to marching band load only was first found. Then the stress due to dead and live load was added as a separate step. The final result is show on table 3.3
load case | max compressive stress (kip/sq inch) | max tensile stress (kip/sq inch) |
marching band (4001 steps) | -44.125 | 45.24 |
dead load | -1.3812 | |
live load | -0.519 | |
combined | -46.02 | 45.24 |
Figure 3.34 shows variation of stress during the 85 seconds of the time history of the marching band.
Additional analysis was done using SAP2000 V15.1 which allows one to visually examine stress diagrams. By selecting this Show stress and selecting this column and point 17 (which is station 0) which is the base of the column, the following diagrams are obtained for different measures at this location. However, these results are obtained before changing the section module of the column to the one we are asked to used in this project. Hence the results shown are not the same found above due to this. These are left here for reference and illustration of this SAP2000 feature.
Now obtained the stress due to dead load and dynamic load. This was done by running the analysis again and now selecting LIVE and DEAD load cases and using the envelope. The result is in this file final_load_result_DEAD_and_LIVE.txt
SAP2000 v15.0.1 5/8/13 2:08:08 Table: Element Forces - Frames Frame Station OutputCase CaseType P V2 V3 T M2 M3 S11Max PtS11Max x2S11Max x3S11Max S11Min PtS11Min x2S11Min x3S11Min FrameElem ElemStation ft Kip Kip Kip Kip-ft Kip-ft Kip-ft Kip/ft2 ft ft Kip/ft2 ft ft ft 11 0.0000 DEAD LinStatic -101.634 0.257 -3.227 -6.3522 -19.2532 26.2485 -81.17 2 -0.50000 0.50000 -155.36 3 0.50000 -0.50000 11-1 0.0000 11 0.0000 LIVE LinStatic -40.210 0.082 -0.040 -1.4303 2.1635 14.0489 -34.51 1 -0.50000 -0.50000 -59.07 4 0.50000 0.50000 11-1 0.0000
These below are obtained from SAP2000 help sections.
Frame element internal forces output convention
SAP2000 S11 description (stress calculations)
SAP2000 shell element internal forces/stresses output convention
These below are documents that describe the project itself and SAP 2000 guide and the original SAP model we obtained to start from.